Whats the answer??
05-09-2005 | 11:53 PM
#5
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The best way to attack something like this is first convert the fractions to eliminate the whole numbers. The way to do that is take the whole number, multiply it by the denominator, and add the numerator. You take this number and put it over the original denominator to get the incomplete fraction. Therefore 5 1/6 will be 5*6+1=31 so the incomplete fraction is 31/6. Likeways 2 1/3 becomes 2*3+1=7 so 7/3. Now you have 31/6 - 7/3, to do this you need to get a common denominator. So 31/6 - 2*(7/3) gives 31/6-14/6. This is simple now, 31/6-14/6 = 17/6. You can leave it like this but proper form dictates you change it to complete fraction form, 6 goes into 17 2 times with 5 left over, so the complete fraction is 2 5/6.
05-10-2005 | 12:05 AM
#6
Originally Posted by 1 Fast SS
The best way to attack something like this is first convert the fractions to eliminate the whole numbers. The way to do that is take the whole number, multiply it by the denominator, and add the numerator. You take this number and put it over the original denominator to get the incomplete fraction. Therefore 5 1/6 will be 5*6+1=31 so the incomplete fraction is 31/6. Likeways 2 1/3 becomes 2*3+1=7 so 7/3. Now you have 31/6 - 7/3, to do this you need to get a common denominator. So 31/6 - 2*(7/3) gives 31/6-14/6. This is simple now, 31/6-14/6 = 17/6. You can leave it like this but proper form dictates you change it to complete fraction form, 6 goes into 17 2 times with 5 left over, so the complete fraction is 2 5/6.
05-10-2005 | 12:28 AM
#9
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Ha yeah thats about right, funny this is in eng you don't even need to know this , calculators are used for everything. I bet theres people in eng at my school that can integrate and do all kinds of crazy math problems but couldn't solve basic fraction questions.
05-10-2005 | 12:08 PM
#11
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Originally Posted by 1 Fast SS
Ha yeah thats about right, funny this is in eng you don't even need to know this , calculators are used for everything. I bet theres people in eng at my school that can integrate and do all kinds of crazy math problems but couldn't solve basic fraction questions.
What school did you take mech. engineering?
05-10-2005 | 12:59 PM
#12
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Originally Posted by 1 Fast SS
The best way to attack something like this is first convert the fractions to eliminate the whole numbers. The way to do that is take the whole number, multiply it by the denominator, and add the numerator. You take this number and put it over the original denominator to get the incomplete fraction. Therefore 5 1/6 will be 5*6+1=31 so the incomplete fraction is 31/6. Likeways 2 1/3 becomes 2*3+1=7 so 7/3. Now you have 31/6 - 7/3, to do this you need to get a common denominator. So 31/6 - 2*(7/3) gives 31/6-14/6. This is simple now, 31/6-14/6 = 17/6. You can leave it like this but proper form dictates you change it to complete fraction form, 6 goes into 17 2 times with 5 left over, so the complete fraction is 2 5/6.
or you can do it the easy way 5 1/6 - 2 1/3 ,.....2 1/3 = 2 2/6
2/6 = 1/3
so really .... 5 1/6 - 2 2/6= 2 5/6
what the hell is this for anyway?!?!?!?
05-10-2005 | 01:16 PM
#13
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HAHAHAHAH ^ YES
thats exactly how i did it....
convert the fraction to common denomiators and then do simple math
for example
5 1/6 - 2 1/3 = ?
we will use common denominator of 6 for this example.... (duh)
5 1/6 = (5*6 + 1)/6 therefore ... 31/6
2 1/3 = (2*3 + 1)/3 therefore ... 7/3
31/6 - 7/3 = ?
now because we are using 6 as common denominator we ask ourselves what can be done to 3 to get 6... so we multiply 3 by 2 to get 6
rule: what is done to the bottom must be done tot the top
so we have
7 *2 14
-- = --
3 *2 6
so once this has been factored we get
31/6 - 14/6
now if u pased gr1 math u'd know 31 - 14 = 17
so you have 17/6 as your answer
and to be more exact.......................... 2 5/6
but this should all be done in ur head in a matter of secconds
thats exactly how i did it....
convert the fraction to common denomiators and then do simple math
for example
5 1/6 - 2 1/3 = ?
we will use common denominator of 6 for this example.... (duh)
5 1/6 = (5*6 + 1)/6 therefore ... 31/6
2 1/3 = (2*3 + 1)/3 therefore ... 7/3
31/6 - 7/3 = ?
now because we are using 6 as common denominator we ask ourselves what can be done to 3 to get 6... so we multiply 3 by 2 to get 6
rule: what is done to the bottom must be done tot the top
so we have
7 *2 14
-- = --
3 *2 6
so once this has been factored we get
31/6 - 14/6
now if u pased gr1 math u'd know 31 - 14 = 17
so you have 17/6 as your answer
and to be more exact.......................... 2 5/6
but this should all be done in ur head in a matter of secconds
05-10-2005 | 06:07 PM
#14
I needed to learn it for a CPT "for acceptance" test at Georgian college earlier this morning. Thank god I passed on hopes and dreams. Just got by..whew.. BTW I seen a full on drift/streeter AE86 in the parking lot with saskatchewan plates. Glad I only had to drive an hour......
05-11-2005 | 12:01 AM
#15
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Originally Posted by blackout_89t
That would be people like me. I can do all the statics and dynamics , but I struggle doing simple math in my head. Its bad.
What school did you take mech. engineering?
What school did you take mech. engineering?